(12x^2+17x-40)=0

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Solution for (12x^2+17x-40)=0 equation:


Simplifying
(12x2 + 17x + -40) = 0

Reorder the terms:
(-40 + 17x + 12x2) = 0

Remove parenthesis around (-40 + 17x + 12x2)
-40 + 17x + 12x2 = 0

Solving
-40 + 17x + 12x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-8 + -3x)(5 + -4x) = 0

Subproblem 1

Set the factor '(-8 + -3x)' equal to zero and attempt to solve: Simplifying -8 + -3x = 0 Solving -8 + -3x = 0 Move all terms containing x to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -3x = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -3x = 0 + 8 -3x = 0 + 8 Combine like terms: 0 + 8 = 8 -3x = 8 Divide each side by '-3'. x = -2.666666667 Simplifying x = -2.666666667

Subproblem 2

Set the factor '(5 + -4x)' equal to zero and attempt to solve: Simplifying 5 + -4x = 0 Solving 5 + -4x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -4x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -4x = 0 + -5 -4x = 0 + -5 Combine like terms: 0 + -5 = -5 -4x = -5 Divide each side by '-4'. x = 1.25 Simplifying x = 1.25

Solution

x = {-2.666666667, 1.25}

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